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E=MC2 for endos

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Old Apr 30, 2006 | 06:39 PM
  #21  
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Re: E=MC2 for endos

Originally Posted by Schwartz
...But I did look at it with a model last night and I think my theroy is wrong.
Now why didnt I think of that
Old Apr 30, 2006 | 07:09 PM
  #22  
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Re: E=MC2 for endos

Depends what kind of model you look at it with, and whether she has implants or not??????
Old May 1, 2006 | 12:46 AM
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Re: E=MC2 for endos

Old May 1, 2006 | 01:34 AM
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Re: E=MC2 for endos

Stooge, If you want, to send me the money, I'll send the steering damper I was going to buy for the RGV(your need is greater) and send it with the bars and clutch cable- next pay I PROMISE!
I'm working 12-7am this week, so call me ya baaaaaaaarrrrrrrstid
96m? far que
Old May 1, 2006 | 07:18 AM
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Re: E=MC2 for endos

OK lets keep this simple.

Bikes roll down hill yeah I can understand that.....

Bikes need to be slowing down to do an endo , even if it is only a small amount otherwise the rear wheel comes down...the slowing of the bike under brakes is what keeps the rear lifted

......so imagine your never-ending hill.Can you endo down it forever?No because the bike needs to be slowing down forever too.Eventually you will come to a stop.





Unless you hit the hill at infinity kph then you would be on a winner


BTW wheres GMB , I did 50m yesterday :YEAH
Old May 1, 2006 | 08:09 AM
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Re: E=MC2 for endos

OK I cant stoppie to save my life but I have been trying to follow this thread and I thought the point was that you need to be up at balance point with very little if not no brake then you will be able to accelerate down a hill. Ofcourse this is would all change depending on how make brake is being used in comparison to the slope of the road... just my thoughts on the theory behind the matter
Old May 1, 2006 | 09:26 AM
  #27  
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Re: E=MC2 for endos

Originally Posted by Ned
BTW wheres GMB , I did 50m yesterday :YEAH
he did
Old May 1, 2006 | 09:26 AM
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Re: E=MC2 for endos

Originally Posted by Ned
OK lets keep this simple.

Bikes roll down hill yeah I can understand that.....

Bikes need to be slowing down to do an endo , even if it is only a small amount otherwise the rear wheel comes down...the slowing of the bike under brakes is what keeps the rear lifted

......so imagine your never-ending hill.Can you endo down it forever?No because the bike needs to be slowing down forever too.Eventually you will come to a stop.





Unless you hit the hill at infinity kph then you would be on a winner


BTW wheres GMB , I did 50m yesterday :YEAH

DUDE!!

I think you're right. You need to be in a state of decell to maintain the height of the rear wheel no matter the angle. Even if you are on a steep enough grade to over come the braking needed to maintain the rear tire off the ground, that decell would be needed to over come gravity.


Inertia or constant state of decell is the only thing keeping the rear tire up.
Old May 1, 2006 | 06:51 PM
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Re: E=MC2 for endos

True, but remember, my point is that the front brakes are on and OFF, which means blipping the front brakes to maintain the height and then off the brakes again on BP. Another way to put it... if your in neutral and going down a road using the brakes just lightly, you will still keep moving at a constant pace.. you wouldnt accelerate, but still keep going and going even with the brakes slightly applied. See my point... brakes slightly applied, not heavily applied like my friend Ned does hehehe
Old May 1, 2006 | 07:55 PM
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Re: E=MC2 for endos

Hummmm.....

I really wonder...
Old May 1, 2006 | 10:23 PM
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Re: E=MC2 for endos

if you are on steep enough hills like in SF you can get it up close to the balance point and keep on rollin all the way down the hill with barely any brake drag at all and sometimes off the brakes and you keep going. and you don't need to be in a constant state of decel to keep it up, you need to decel hard to get it up there and if you can roll good stoppies once it gets up there you are tapping the brake from time to time. if you got a good stabilizer cranked way up I'm sure it's possible. you just gotta get that thing up to the balance point. if you ever start to flip over and you have enough reaction time to do this, you can dump the clutch and crack the bike wide open and it will bring you back down. saved my *** a few times.
Old May 1, 2006 | 11:23 PM
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Re: E=MC2 for endos

Originally Posted by MikeOnTheBike
if you are on steep enough hills like in SF you can get it up close to the balance point and keep on rollin all the way down the hill with barely any brake drag at all and sometimes off the brakes and you keep going. and you don't need to be in a constant state of decel to keep it up, you need to decel hard to get it up there and if you can roll good stoppies once it gets up there you are tapping the brake from time to time. if you got a good stabilizer cranked way up I'm sure it's possible. you just gotta get that thing up to the balance point. if you ever start to flip over and you have enough reaction time to do this, you can dump the clutch and crack the bike wide open and it will bring you back down. saved my *** a few times.

Not a true statment.

Decell is the ONLY thing keeping the rear tire/wheel off the ground.
Old May 2, 2006 | 04:43 AM
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Re: E=MC2 for endos

Surely Stooge is without question correct on this one!

This is somehting I've played with in my head for a while now too.

I think the reason for the confusion is thinking that an endo need deceleration to keep it just before the BP. not true - it's a FORCE that it needs... which in tha case of a normal endo.. this ofrce is supplie by the deceleration.

Down a hill the force is supplied by gravity pulling you down the hill - at a if you did this on a variety of different hills each with a steeper gradied (and use the same amount of brake on all of them) then on the flatter ones you would roll to a stop.... but at some point there is a hill steep enough to provide (theoretically) endless endo's.

If the force slowing the bike down it less than the force of gravity pulling the weight of the bike/rider down the hill then the bike will speed up regardles of how many wheels its on. [It's friction verses gravity]

I need to find me a hill!!! and roll my endo's out longer.

Hill and a camcorder Stooge - I'm convinced you're right :YEAH
Old May 2, 2006 | 05:07 AM
  #34  
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Re: E=MC2 for endos

Thanks for your post Nick. I think this one is going to be one of them 'try it and know' things. I would be also finding it difficult to understand but I know from the feel what its doing. If your gona try this, of course be safe from flipping. I think the same principal applies to coasters... if you got a hill and can balance the coaster without needing rear brake, you can coaster endlessly.
Old May 2, 2006 | 05:07 AM
  #35  
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Re: E=MC2 for endos

Originally Posted by BritishNick
If the force slowing the bike down is less than the force of gravity pulling the weight of the bike/rider down the hill then the bike will speed up regardles of how many wheels its on. [It's friction verses gravity]
There is a bit more to it than that but all-in-all..... but yep thats about it.
Old May 2, 2006 | 05:27 AM
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Re: E=MC2 for endos

I'm so lost... oh well, interesting theroy. Maybe I should have paid closer attention in school...
Old May 2, 2006 | 06:47 AM
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Re: E=MC2 for endos

Originally Posted by BritishNick
Surely Stooge is without question correct on this one!

This is somehting I've played with in my head for a while now too.

I think the reason for the confusion is thinking that an endo need deceleration to keep it just before the BP. not true - it's a FORCE that it needs... which in tha case of a normal endo.. this ofrce is supplie by the deceleration.

Down a hill the force is supplied by gravity pulling you down the hill - at a if you did this on a variety of different hills each with a steeper gradied (and use the same amount of brake on all of them) then on the flatter ones you would roll to a stop.... but at some point there is a hill steep enough to provide (theoretically) endless endo's.

If the force slowing the bike down it less than the force of gravity pulling the weight of the bike/rider down the hill then the bike will speed up regardles of how many wheels its on. [It's friction verses gravity]

I need to find me a hill!!! and roll my endo's out longer.

Hill and a camcorder Stooge - I'm convinced you're right :YEAH
Makes sense....now lets throw another fish in here....

So in theory....you should be able to speed up and slow down on a rather steep hill while maintaining a consistant stoppie....
Old May 2, 2006 | 09:47 AM
  #38  
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Re: E=MC2 for endos

Originally Posted by Bender
Makes sense....now lets throw another fish in here....

So in theory....you should be able to speed up and slow down on a rather steep hill while maintaining a consistant stoppie....
that's how it works in my head...

now all I need is a big hill and an ability to roll one out for more than 40meters - then I can see for real.

would love to see an atempt of vid if u get em
Old May 2, 2006 | 10:14 AM
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Re: E=MC2 for endos

Just for the record, I don't agree with this current threoy.

Not completly disagreeing, just a friendly convesation. Very interesting topic.



I still think the only force keeping the rear wheele off the ground is Decell.

Again I could easly be wrong. Where is the phisyic major.
Old May 2, 2006 | 10:57 AM
  #40  
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Re: E=MC2 for endos

Originally Posted by Schwartz
Just for the record, I don't agree with this current threoy.

Not completly disagreeing, just a friendly convesation. Very interesting topic.



I still think the only force keeping the rear wheele off the ground is Decell.

Again I could easly be wrong. Where is the phisyic major.
agreed - someone must know someone who knows the sums here???

okay so maybe we're both right !?!?!?! lets say you do need deceleration (a braking force) to endo just under BP... buton a hill that braking force if ofset by gravity pushing the weight of the bike down the hill... so as long as the force of gravity on the weight is greater than the force of friction from the brake then : Jobs a good en ?

okay I'm out of idea's now.... where's the realy clever people?



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